# The concession stand is selling hot dogs and hamburgers during a game. At halftime, they sold a total of 78 hot dogs and hamburgers and brought in $105.50. how many of each item did they sell if hamburgers sold for $1.50 and hot dogs sold for $1.25?

##### 1 Answer

Jul 5, 2016

#### Answer:

The concession stand sold

#### Explanation:

The first thing to do in algebraic problems is assign variables to things we don't know, so let's start there:

- We don't know how many hot dogs the concession stand sold, so we will call that number
#d# . - We don't know how many hamburgers the concession stand sold, so we will call that number
#h# .

Now we translate the statements into algebraic equations:

- The number of hot dogs and hamburgers that were sold is
#78# , so#d+h=78# . - If each hot dog is sold for
#1.25# , then the total revenue from hot dogs is given by#1.25d# . In the same way, the total revenue from hamburgers is#1.50h# . The total revenue from both hot dogs and hamburgers should be the sum of these, and since we are told the total revenue is#105.50# , we can say#1.25d+1.5h=105.5# .

We now have a system of two linear equations:

We can solve it using several methods, though I'm going to go with substitution. Use the first equation to solve for

Now plug this in for

Solving for

Since

The concession stand therefore sold