The curved portion is smooth and the horizontal portion are rough.The block is released from P.At what distance from A the block will stop. ( μ=0.2) ?
2 Answers
Explanation:
During the fall from
Applying law of conservation of energy,
we can say,
So,
Now,the frictional force that will be acting on the block is
So,deceleration while going along the horizontal part will be
So,if it stops by going distance
we get,
So,
But,givn length of the horizontal part is
So,
So,at point
Now,if it goes up by height
So,
Now,after reaching that point it will again come down and gain the same velocity at point
So,
So,it will still not come to rest still now, so lets find velocity after moving
so,
So,after rising up when coming down,it will have same velocity at
So,this time if it stops after going
or,
Almost about
1m from A
Explanation:
The initial total energy is just the potential energy :
Thus the block will cover the 2m stretch of rough ground twice and then travel an extra distance of 1 m before coming to a halt (in between it will climb up and down the two curved surfaces, but since these are smooth, this will not dissipate any energy ).