The decomposition of KClO3(s) into KCl(s) and O2(g) with an 85% yield. How many moles of KClO3 must be used to generate 3.50 moles of O2?
Here, the equation of the reaction is
Now as you see, the yield of the reaction is 85% which means that out of the number of moles of the products to be given out, only 80% is obtained.
In order to obtain 3.50 moles of
So, if the reaction gave 100% of the yield, no. of moles of
Now, 3 molecules of
No. of moles of 1 molecule of
No. of moles of 2 molecules of
Therefore, 2.75 moles of