Question

The diameter of a chlorine atom is 200. pm. How many chlorine atoms are required to line up end to end to stretch a distance of 1.0 mm?

Answer 1

Good question. `(1xx10^-3*m)/(200xx10^-12*m)`

Explanation:

`(1xx10^-3*m)/(200xx10^-12*m)` `=` `??`

A more realistic measurement might consider the chlorine molecule. `Cl_2` has a bond length of `2.00xx10^-10` `m`. How many of these ened to end will fit in a `mm`. Pretty vast but not infinite.