# The empirical formula of a compound is determined to be "C"_2"H"_3, and its molecular mass is found to be 54.10 g/mol. How do you determine the molecular formula of the compound?

Nov 29, 2016

${\text{C"_4"H}}_{6}$
$\frac{54.1}{27} \approx 2$
${\text{C"_2"H"_3xx2="C"_4"H}}_{6}$