Question

The ends of diameter (6,5) and (-12,-5), how do you find the equation of this circle?

Answer 1

`(x+3)^2+y^2=106`

Explanation:

The centre of the circle is the midpoint of the points.
i.e. (-3,0)

The radius of the circle is half the distance between the points.

Distance = `sqrt((6--12)^2+(5--5)^2)`
`= sqrt(18^2+10^2)=sqrt(324+100)=sqrt(424)=2sqrt106`

Radius = `sqrt(106)`

Equation: `(x+3)^2+y^2=106`