Question

The first 31st term of a geometric sequence is 123 and the 32nd term is 1107. What is the 33rd term?

Answer 1

`9963`

Explanation:

We can find the common ratio of the geometric sequence by taking the ratio of any term with the preceding term.

So in this case we can say that the ratio `r=T_32/T_31=1107/123=9`.

Consequently, the next term will be the previous term multiplied by the common ratio.

So in this case, `T_33=9*T_32`

`=9xx1107`

`=9963`