The first three terms of an arithmetic series are x-1, 5x-3, 4x+5, how do you find the sixth term?

1 Answer

The sixth term is 31

Explanation:

It should be

5x3(x1)=4x+5(5x3)4x2=8x5x=10x=2

Hence the first three terms are 21=1,523=7,42+5=13

So it is an arithmetic series with first term a1=1 and ratio r=6

hence

a6=a1+(61)6=1+30=31