The first three terms of an arithmetic series are x-1, 5x-3, 4x+5, how do you find the sixth term?

1 Answer

The sixth term is 3131

Explanation:

It should be

5x-3-(x-1)=4x+5-(5x-3)=>4x-2=8-x=>5x=10=>x=25x3(x1)=4x+5(5x3)4x2=8x5x=10x=2

Hence the first three terms are 2-1=121=1,5*2-3=7523=7,4*2+5=1342+5=13

So it is an arithmetic series with first term a_1=1a1=1 and ratio r=6r=6

hence

a_6=a_1+(6-1)*6=1+30=31a6=a1+(61)6=1+30=31