# The fish population of lake henry is decreasing at a rate of 4% per year. in 2002 there were about 1,250 fish. write an exponential decay function to model this situation then find the population in 2008?

##### 2 Answers

I found

#### Explanation:

I tried considering 2002 as the time

In 2008 we will have

#### Explanation:

A loss of

#p(t) = 1250 * 0.96^t#

where

#0.96^6 ~~ 0.7828#

so

If we want to express this in terms of

#ln p(t) = ln (1250*0.96^t) = ln(1250) + t ln (0.96)#

Then taking exponents:

#p(t) = e^(ln p(t)) = e^(ln(1250) + t ln (0.96)) = 1250 e^(ln(0.96)t)#

#ln(0.96) ~~ -0.040822#

So:

#p(t) ~~ 1250 e^(-0.040822t)#