The force applied against a moving object travelling on a linear path is given by F(x)=2x+xe^x . How much work would it take to move the object over x in [1,2 ] ?

1 Answer
Dec 31, 2017

W= 3+e^2 Joule

Explanation:

F(x) = 2x+xe^x

As we know,

dW= vec F * vec(dx)

Integrating both sides

W= int_1^2(2x+xe^x)dx

W= [x^2]_1^2+int_1^2xe^xdx

Applying by-parts by ILATE rule,

W= [x^2]_1^2+[xe^x]_1^2-int_1^2e^xdx

W= [x^2]_1^2+[xe^x]_1^2-[e^x]_1^2

W= 4-1+2e^2-e-e^2+e Joule

W= 3+e^2 Joule