The force applied against a moving object travelling on a linear path is given by #F(x)= x^2+e^x #. How much work would it take to move the object over #x in [0, 5] #? Physics Work and Energy Work 1 Answer sjc Oct 26, 2017 Answer: see below Explanation: for a variable force Work done#=int_a^b(F(x)dx# in this case Work done#=int_0^5(x^2+e^x)dx# #=[1/3x^3+e^x]_0^5# #=[1/3x^3+e^x]^5-[1/3x^3+e^x]_0# #=1/3 5^3-e^5-0-e^0# #=125/3-1-e^5# #=(122/3-e^5)J# Related questions What is a force? What are some examples of work? What are some examples of displacement? How are force, energy, and work are related? How can I calculate the displacement of an object? How are work and kinetic energy related? How do you calculate the displacement of water? How do you calculate the force of gravity between two objects? Why is work negative? 55,000J of work is done to move a rock 25m. How much force was applied? See all questions in Work Impact of this question 137 views around the world You can reuse this answer Creative Commons License