The force applied against a moving object travelling on a linear path is given by #F(x)= 2x^3+x#. How much work would it take to move the object over #x in [0, 4] #?

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Answer 1 · 2016-02-16T20:31:35

#W=int _0^4 F(x)*d x#
#W=int_0^4 (2x^3+x)*d x#
#W=[1/2*x^4+1/2*x^2]_0^4#
#W=[1/2*4^4+1/2*4^2]-[1/2*0+1/2*0]#
#W=(128+8)-0#
#W=132 J#