The force applied against a moving object travelling on a linear path is given by F(x)= 2x^3+x. How much work would it take to move the object over x in [2, 3] ?

1 Answer
Mar 13, 2018

"35 Joule"

Explanation:

Small work done by force for a small distance dx is given by

dW = F.dx

Total work done is

W = intdW = intF.dx

W = int_2^3(2x^3 + x)dx

W = [(2x^4)/4 + x^2/2]_2^3

W = [x^4/2 + x^2/2]_2^3

W = 1/2[x^4 + x^2]_2^3

W = 1/2[(3^4 - 2^4) + (3^2 - 2^2)] = "35 Joule"