The force applied against a moving object travelling on a linear path is given by F(x)= 2x^3+x. How much work would it take to move the object over x in [2, 3] ?
1 Answer
Mar 13, 2018
Explanation:
Small work done by force for a small distance
dW = F.dx
Total work done is
W = intdW = intF.dx
W = int_2^3(2x^3 + x)dx
W = [(2x^4)/4 + x^2/2]_2^3
W = [x^4/2 + x^2/2]_2^3
W = 1/2[x^4 + x^2]_2^3
W = 1/2[(3^4 - 2^4) + (3^2 - 2^2)] = "35 Joule"