The force applied against a moving object travelling on a linear path is given by #F(x)= sinx + 2 #. How much work would it take to move the object over #x in [ 0, (7 pi) / 8 ] #?

1 Answer
Feb 2, 2016

Answer:

W = int_0^(7/8pi) (sinx+2) dx# # W = ((-cos x)+ 2x)|_0^(7/8pi) # #W = .00115 + 7/4pi #

Explanation:

Work #W = int_a^bF(x) do #
#F(x) = sinx + 2; a = 0; b = 7/8pi#
# W = int_0^(7/8pi) (sinx+2) dx#
# W = ((-cos x)+ 2x)|_0^(7/8pi) #
#W = .00115 + 7/4pi #