The force applied against a moving object travelling on a linear path is given by #F(x)= sinx + 2 #. How much work would it take to move the object over #x in [ 0, (13 pi) / 8 ] #?

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Answer 1 · 2017-06-05T12:16:37

The work is #=10.83J#

The work is

#DeltaW=FDeltax#

#F=sinx+2#

#DeltaW=(sinx+2)Deltax#

#W=int_0^(13/8pi)(sinx+2)dx#

#=[-cosx+2x]_0^(13/8pi)#

#=(-cos(13/8pi)+13/4pi)-(-cos0+0)#

#=13/4pi+1-cos(13/8pi)#

#=10.83J#