Question

The force applied against a moving object travelling on a linear path is given by `F(x)=3x+e^x`. How much work would it take to move the object over `x in [0, 3 ]`?

Answer 1

The work `=25/2+e^3`

Explanation:

The work done = force*distance
The unit work `dW=F(x)*dx`
`:. dW=(3x+e^x)dx`
`W=int_0^3(3x+e^x)dx= [(3x^2)/2+e^x ]_0^3`
`=(27/2+e^3-e^0)`
`=25/2+e^3`