The force applied against an object moving horizontally on a linear path is described by F(x)=4e^x+ 1/x . By how much does the object's kinetic energy change as the object moves from x in [ 1, 3 ]? Physics Work and Energy Energy 1 Answer Narad T. Jul 16, 2017 The change in kinetic energy is =70.57Jf Explanation: We need inte^xdx=e^x+C int(1/x)dx=ln(|x|)+C The change in Kinetic Energy is equal to the work done. DeltaE=W=F*d W=int_1^3(4e^x+1/x)dx =[4e^x+lnx]_1^3 =(4e^3+ln3)-(4e+ln1) =70.57J Answer link Related questions How do matter and energy interact? Question #50ca2 Question #242cf Question #5038d Question #50391 What is potential energy? Question #d6576 Question #50cae Question #50cb2 Question #50cb6 See all questions in Energy Impact of this question 1550 views around the world You can reuse this answer Creative Commons License