The gas inside of a container exerts #12 Pa# of pressure and is at a temperature of #35 ^o K#. If the temperature of the gas changes to #20 ^oK# with no change in the container's volume, what is the new pressure of the gas?

1 Answer
Dec 31, 2016

Answer:

#P_2 = 6.86 Pa#

Explanation:

The ideal gas laws (Charles' Law) state:

#(P_1 * V_1)/T_1 = (P_2 * V_2)/T_2#

Where #P_1,_2# are pressures – units don't matter in this case as long as they are consistent, because this is a ratio.
#V_1,_2# are the corresponding volumes in Liters
#T_1,_2# are the temperatures in degrees

With a constant container volume, Charles' Law becomes simply:
#P_1/T_1 = P_2/T_2#

Rearrange for your known values:
#P_2 = P_1 * T_2/T_1#

#P_2 = 12 * 20/35#

#P_2 = 6.86 Pa#