The gas inside of a container exerts #14 Pa# of pressure and is at a temperature of #220 ^o C#. If the temperature of the gas changes to #150 ^oC# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2017-05-08T10:23:34

The new pressure is #=3.4Pa#

We apply Gay Lussac's Law

#P_1/T_1=P_2/T_2#

The initial pressure is #P_1=14Pa#

The initial temperature is #T_1=220+273=493K#

The final temperature is #T_2=150+273=423K#

The final pressure is

#P_2=T_2/T_1*P_1#

#=423/493*14#

#=3.4Pa#