# The gas inside of a container exerts 15 Pa of pressure and is at a temperature of 450 ^o K. If the temperature of the gas changes to 240 ^oC with no change in the container's volume, what is the new pressure of the gas?

Apr 20, 2017

The new pressure is $= 17.1 P a$

#### Explanation:

We apply Gay Lussac's Law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$

Initial pressure is ${P}_{1} = 15 P a$

Initial temperature is ${T}_{1} = 450 K$

Final temperature is ${T}_{2} = 240 + 273 = 513 K$

The final pressure is

${P}_{2} = {T}_{2} / {T}_{1} \cdot {P}_{1} = \frac{513}{450} \cdot 15 = 17.1 P a$