Question

The gas inside of a container exerts `15 Pa` of pressure and is at a temperature of `450 ^o K`. If the pressure in the container changes to `16 Pa` with no change in the container's volume, what is the new temperature of the gas?

Answer 1

`"The new temperature of gas :"480 ^o K`

Explanation:

`P_i:"The initial pressure of gas"`
`P_l:"The last pressure of gas"`
`T_i:"The initial temperature of gas"`
`T_l:"The last temperature of gas"`
`"Let us use the formula below"`

`P_i/T_i=P_l/T_l`

`"Plug the given values into equation"`

`P_i=15Pa`
`P_l=16Pa`

`T_i=450 ^o K`
`T_f=?`

`15/450=16/T_f`

`15*T_f=16*450`

`T_f=(16*450)/15`

`T_f=480^o K`