# The gas inside of a container exerts 15 Pa of pressure and is at a temperature of 50 ^o K. If the temperature of the gas changes to 90 ^oK with no change in the container's volume, what is the new pressure of the gas?

Oct 4, 2016

$\text{The final pressure of gas is 27 Pa.}$

#### Explanation:

$\text{use the formula : } {P}_{i} / {T}_{i} = {P}_{f} / {T}_{f}$

${P}_{i} : \text{initial pressure}$

${P}_{f} : \text{final pressure}$

${T}_{i} : \text{initial temperature}$

${T}_{f} : \text{final temperature}$

${P}_{i} = 15 \text{ } P a$

P_f=?" "Pa

${T}_{i} = 50 \text{ } {K}^{o}$

${T}_{f} = 90 \text{ } {K}^{o}$

$\text{plug given values:}$

$\frac{15}{50} = {P}_{f} / 90$

${P}_{f} \cdot \cancel{5} \cancel{0} = \cancel{15} \cdot 9 \cancel{0}$

${P}_{f} = 3 \cdot 9$

${P}_{f} = 27 \text{ } P a$