Question

The gas inside of a container exerts `15 Pa` of pressure and is at a temperature of `45 ^o K`. If the temperature of the gas changes to `90 ^oK` with no change in the container's volume, what is the new pressure of the gas?

Answer 1

`30"Pa"`

Explanation:

First the gas to be ideal. Then, from Gay-Lussac's Law, we know that

`p_1/T_1 = p_2/T_2`

So

`(15"Pa")/(45"K") = p_2/(90"K")`

`p_2 = 30"Pa"`