# The gas inside of a container exerts #18 Pa# of pressure and is at a temperature of #360 ^o K#. If the pressure in the container changes to #27 Pa# with no change in the container's volume, what is the new temperature of the gas?

##### 2 Answers

#### Answer:

The final temperature,

#### Explanation:

This question is an example of Gay-Lussac's gas law, which states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. This means that if the pressure increases, so does the temperature, and vice-versa. The equation to use in order to answer your question is:

**Organize your data.**

**Given**

**Unknown:**

**Solution**

Rearrange the equation to isolate

As you can see, as the pressure increased, so did the temperature.

#### Answer:

#### Explanation:

We can use the temperature-pressure relationship of gases illustrated by Gay-Lussac's law:

At constant volume, the temperature and pressure of a fixed quantity of gas are directly proportional to each other, which is explained by the kinetic-molecular theory.

We can rearrange this equation to solve for the final temperature

and finally, plug in the known variables to find the temperature.