The gas inside of a container exerts #"24 Pa"# of pressure and is at a temperature of #"320 K"#. If the pressure in the container changes to #"32 Pa"# with no change in the container's volume, what is the new temperature of the gas?
The final temperature is 430 K.
This is an example of Guy-Lussac's law, which states that as long as volume is constant, the pressure and temperature of a gas are directly proportional. This means that if the pressure goes up, so does the temperature and vice-versa. The equation for Gay-Lussac's law is
Rearrange the equation to isolate