The gas inside of a container exerts $24 Pa$ of pressure and is at a temperature of $210 ^o K$ . If the pressure in the container changes to $64 Pa$ with no change in the container's volume, what is the new temperature of the gas?

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Answer 1 · 2016-04-08T18:41:09

$T_2=560" "^o K$

$P_1=24 " "Pa$
$T_1=210" "^o K$

$P_2=64 " "Pa$
$T_2=?$

$P_1/T_1=P_2/T_2$

$24/210=64/T_2$

$T_2=(210*64)/24$

$T_2=560" "^o K$

The gas inside of a container exerts 24 Pa24 Pa of pressure and is at a temperature of 210 ^o K210 ^o K. If the pressure in the container changes to 64 Pa64 Pa with no change in the container's volume, what is the new temperature of the gas?