The gas inside of a container exerts $25 Pa$ of pressure and is at a temperature of $750 ^o K$ . If the temperature of the gas changes to $150 ^oC$ with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2017-04-22T14:05:36

The pressure is $=14.1Pa$

We apply Gay Lussac's Law

$P_1/T_1=P_2/T_2$

The initial pressure is $P_1=25Pa$

The initial temperature is $T_1=750K$

The final temperature is $T_2=150+273=423K$

The final pressure is

$P_2=T_2/T_1*P_1$

$=423/750*25=14.1Pa$

The gas inside of a container exerts 25 Pa25 Pa of pressure and is at a temperature of 750 ^o K750 ^o K. If the temperature of the gas changes to 150 ^oC150 ^oC with no change in the container's volume, what is the new pressure of the gas?