The gas inside of a container exerts #3 Pa# of pressure and is at a temperature of #360 ^o K#. If the temperature of the gas changes to #240 ^oC# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2016-10-20T06:19:50

#P_f=4.275Pa#

#P_i:"initial pressure"#

#T_i:"initial temperature"#

#T_f:"final temperature"#

#P_f:"final pressure"#

#P_i=3Pa#
#T_i=360 ^o K#

#T_f=240^o C#

#"convert " ^o C " to " ^o K#

#T_f=240+273=513^o K#

#P_i/T_i=P_f/T_f#

#3/360=P_f/513#

#P_f*360=3*513#

#P_f=(3*513)/360#

#P_f=4.275Pa#