# The gas inside of a container exerts 3 Pa of pressure and is at a temperature of 360 ^o K. If the temperature of the gas changes to 240 ^oC with no change in the container's volume, what is the new pressure of the gas?

##### 1 Answer
Oct 20, 2016

${P}_{f} = 4.275 P a$

#### Explanation:

${P}_{i} : \text{initial pressure}$

${T}_{i} : \text{initial temperature}$

${T}_{f} : \text{final temperature}$

${P}_{f} : \text{final pressure}$

${P}_{i} = 3 P a$
${T}_{i} = {360}^{o} K$

${T}_{f} = {240}^{o} C$

${\text{convert " ^o C " to }}^{o} K$

${T}_{f} = 240 + 273 = {513}^{o} K$

${P}_{i} / {T}_{i} = {P}_{f} / {T}_{f}$

$\frac{3}{360} = {P}_{f} / 513$

${P}_{f} \cdot 360 = 3 \cdot 513$

${P}_{f} = \frac{3 \cdot 513}{360}$

${P}_{f} = 4.275 P a$