Question

The gas inside of a container exerts `3 Pa` of pressure and is at a temperature of `360 ^o K`. If the temperature of the gas changes to `240 ^oC` with no change in the container's volume, what is the new pressure of the gas?

Answer 1

`P_f=4.275Pa`

Explanation:

`P_i:"initial pressure"`

`T_i:"initial temperature"`

`T_f:"final temperature"`

`P_f:"final pressure"`

`P_i=3Pa`
`T_i=360 ^o K`

`T_f=240^o C`

`"convert " ^o C " to " ^o K`

`T_f=240+273=513^o K`

`P_i/T_i=P_f/T_f`

`3/360=P_f/513`

`P_f*360=3*513`

`P_f=(3*513)/360`

`P_f=4.275Pa`