Question

The gas inside of a container exerts `3 Pa` of pressure and is at a temperature of `480 ^o K`. If the temperature of the gas changes to `240 ^oC` with no change in the container's volume, what is the new pressure of the gas?

Answer 1

The new pressure is `=3.2Pa`

Explanation:

Use the equation `P_1/T_1=P_2/T_2`
which we derive from `PV=nRT` since `V` and `n` do not change
`P_1=3 Pa`
`T_1=480K`
`T_2=240+273=513K`
`P_2=3*513/480=3.2 Pa`