The gas inside of a container exerts 3 Pa of pressure and is at a temperature of 480 ^o K. If the temperature of the gas changes to 240 ^oC with no change in the container's volume, what is the new pressure of the gas?

Nov 9, 2016

The new pressure is $= 3.2 P a$

Explanation:

Use the equation ${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$
which we derive from $P V = n R T$ since $V$ and $n$ do not change
${P}_{1} = 3 P a$
${T}_{1} = 480 K$
${T}_{2} = 240 + 273 = 513 K$
${P}_{2} = 3 \cdot \frac{513}{480} = 3.2 P a$