# The gas inside of a container exerts 3 Pa of pressure and is at a temperature of 430 ^o K. If the temperature of the gas changes to 220 ^oC with no change in the container's volume, what is the new pressure of the gas?

Mar 11, 2016

${P}_{2} \cong 3 , 44 P a$
${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$
$\frac{3}{430} = {P}_{2} / \left(220 + 273\right)$
$\frac{3}{430} = {P}_{2} / 493$
${P}_{2} = \frac{3 \cdot 493}{430}$
${P}_{2} \cong 3 , 44 P a$