Question

The gas inside of a container exerts `36 Pa` of pressure and is at a temperature of `75 ^o K`. If the temperature of the gas changes to `150 ^oK` with no change in the container's volume, what is the new pressure of the gas?

Answer 1

`P_2~=15,5 k Pa`

Explanation:

`75^o=273+75=348^o K`
`P_1/T_1=P_2/T_2`
`36/348=P_2/150`
`P_2=(150*36)/348`
`P_2~=15,5 k Pa`