# The gas inside of a container exerts 4 Pa of pressure and is at a temperature of 120 ^o C. If the temperature of the gas changes to 150 ^oK with no change in the container's volume, what is the new pressure of the gas?

May 26, 2017

The new pressure is $= 1.53 P a$

#### Explanation:

We apply Gay Lussac's Law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$

The initial pressure is ${P}_{1} = 4 P a$

The initial temperature is ${T}_{1} = 120 + 273 = 393 K$

The final temperature is ${T}_{2} = 150 K$

The final pressure is

${P}_{2} = {T}_{2} / {T}_{1} \cdot {P}_{1}$

$= \frac{150}{393} \cdot 4$

$= 1.53 P a$