The gas inside of a container exerts $4 Pa$ of pressure and is at a temperature of $220 ^o C$ . If the temperature of the gas changes to $150 ^oC$ with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2016-08-17T21:10:05

$P_f=3.43" "Pa$

$P_i:"initial pressure (Pa)"$
$P_f:"final pressure (Pa)"$
$T_i:"initial temperature (Kelvin)"$
$T_f:"final temperature (Kelvin)"$

$"given data:"$
$P_i=4Pa$
$P_f=?$
$T_i=220+273=493 " "^o K$
$T_f=150+273=423" "^o K$

$"We can use the Gay-Lussac's Law to calculate the problem"$

$P_i/T_i=P_f/T_f$

$4/493=P_f/423$

$P_f=(4*423)/493$

$P_f=3.43" "Pa$

The gas inside of a container exerts 4 Pa4 Pa of pressure and is at a temperature of 220 ^o C220 ^o C. If the temperature of the gas changes to 150 ^oC150 ^oC with no change in the container's volume, what is the new pressure of the gas?