# The gas inside of a container exerts 4 Pa of pressure and is at a temperature of 220 ^o C. If the temperature of the gas changes to 150 ^oC with no change in the container's volume, what is the new pressure of the gas?

Aug 17, 2016

${P}_{f} = 3.43 \text{ } P a$

#### Explanation:

${P}_{i} : \text{initial pressure (Pa)}$
${P}_{f} : \text{final pressure (Pa)}$
${T}_{i} : \text{initial temperature (Kelvin)}$
${T}_{f} : \text{final temperature (Kelvin)}$

$\text{given data:}$
${P}_{i} = 4 P a$
P_f=?
${T}_{i} = 220 + 273 = 493 {\text{ }}^{o} K$
${T}_{f} = 150 + 273 = 423 {\text{ }}^{o} K$

$\text{We can use the Gay-Lussac's Law to calculate the problem}$

${P}_{i} / {T}_{i} = {P}_{f} / {T}_{f}$

$\frac{4}{493} = {P}_{f} / 423$

${P}_{f} = \frac{4 \cdot 423}{493}$

${P}_{f} = 3.43 \text{ } P a$