The gas inside of a container exerts #6 Pa# of pressure and is at a temperature of #120 ^o C#. If the temperature of the gas changes to #180 ^oK# with no change in the container's volume, what is the new pressure of the gas?

1 Answer
Apr 18, 2017

Answer:

#"New pressure of the gas is 2.75Pa"#

Explanation:

#"We should use the Gay-Lussac's law to solve this problem."#

#P_i/T_i=P_f/T_f#

#P_i:"The initial pressure of gas "P_i=6Pa#
#T_i:"The initial temperature of gas "T_i=120^o C#

#"We should change "^o C " to " ^o K "(Kelvin)"#

#T_i=120+273=393^o K#

#T_f:"Final temperature of gas "T_f=180^o K#

#P_f:"Final pressure of gas "P_f=?#

#6/393=P_f/180#

#6*180=393*P_f#

#P_f=(6*180)/393#

#P_f=2.75Pa#