# The gas inside of a container exerts 7 Pa of pressure and is at a temperature of 120 ^o K. If the pressure in the container changes to 49 Pa with no change in the container's volume, what is the new temperature of the gas?

Nov 16, 2016

840K

#### Explanation:

Considering the gas shows ideal behaviour

Ideal Gas equation is PV = nRT

In your case volume and number of moles is constant.
R = universal gas constant.

$\therefore$ ${P}_{1} / {P}_{2} = {T}_{1} / {T}_{2}$

$\frac{7}{49} = \frac{120}{T} _ 2$

$\therefore {T}_{2} = 840 K$