Question

The gas inside of a container exerts `8 Pa` of pressure and is at a temperature of `45 ^o K`. If the temperature of the gas changes to `80 ^oK`, what is the new pressure of the gas?

Answer 1

With a constant container volume, Charles' Law becomes simply:
`P_1/T_1 = P_2/T_2`
Rearrange for your known values:
`P_2 = P_1 * T_2/T_1`

Explanation:

The ideal gas laws (Charles' Law) state:
`(P_1 * V_1)/T_1 = (P_2 * V_2)/T_2`
Where `P_1,_2` are pressures – units don't matter in this case as long as they are consistent, because this is a ratio.
`V_1,_2` are the corresponding volumes in Liters
`T_1,_2` are the temperatures in degrees Kelvin