The gas inside of a container exerts #8 Pa# of pressure and is at a temperature of #45 ^o K#. If the temperature of the gas changes to #80 ^oK#, what is the new pressure of the gas?

1 Answer
Feb 18, 2016

Answer:

With a constant container volume, Charles' Law becomes simply:
#P_1/T_1 = P_2/T_2#
Rearrange for your known values:
#P_2 = P_1 * T_2/T_1#

Explanation:

The ideal gas laws (Charles' Law) state:
#(P_1 * V_1)/T_1 = (P_2 * V_2)/T_2#
Where #P_1,_2# are pressures – units don't matter in this case as long as they are consistent, because this is a ratio.
#V_1,_2# are the corresponding volumes in Liters
#T_1,_2# are the temperatures in degrees Kelvin