# The gas inside of a container exerts 8 Pa of pressure and is at a temperature of 35 ^o K. If the temperature of the gas changes to 80 ^oK, what is the new pressure of the gas?

Jan 9, 2018

The new pressure is $= 18.3 P a$

#### Explanation:

Apply Gay Lussac's Law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$, $\text{at constant volume}$

The initial pressure is $= {P}_{1} = 8 P a$

The initial temperature is ${T}_{1} = 35 K$

The final temperature is ${T}_{2} = 80 P a$

Therefore,

The final pressure is

${P}_{2} = {T}_{2} / {T}_{1} \cdot {P}_{1} = \frac{80}{35} \cdot 8 = 18.3 P a$