The gas inside of a container exerts #8 Pa# of pressure and is at a temperature of #220 ^o K#. If the temperature of the gas changes to #20 ^oC# with no change in the container's volume, what is the new pressure of the gas?
I assume that we are working with a perfect gas.
The process is called isochoric (it means that mantains the volume unchanged). Those process follow the law
This mean that if we have an initial pressure and temperature
In our case we have
and we want to know
It is always better to work in the International System then we convert the Celsius in Kelvin adding
Before solving the equation of the isochoric process we can notice that the temperature is increasing of 73.15 K from 220 K to 293.15 K. If we warm up a gas we expect that the pressure increase because the particles of the gas move faster. So at the end we should find something bigger than 8 Pa.
We can write our equation for isochoric process