# The gas inside of a container exerts 8 Pa of pressure and is at a temperature of 210 ^o K. If the temperature of the gas changes to 35 ^oC with no change in the container's volume, what is the new pressure of the gas?

Jun 4, 2016

${P}_{f} = 11.73 \text{ } P a$

#### Explanation:

${P}_{i} = 8 \text{ "Pa" initial pressure}$

${T}_{1} = 210 \text{ "^o K" initial temperature}$

${T}_{2} = 35 {\text{ "^o C" ; "T_2=35+273=308 " }}^{o} K$

P_f=?" final pressure"

${P}_{i} / {T}_{i} = {P}_{f} / {T}_{f}$

$\frac{8}{210} = {P}_{f} / 308$

${P}_{f} = \frac{8 \cdot 308}{210}$

${P}_{f} = 11.73 \text{ } P a$