The gas inside of a container exerts $8 Pa$ of pressure and is at a temperature of $210 ^o K$ . If the temperature of the gas changes to $35 ^oC$ with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2016-06-04T10:21:53

$P_f=11.73" "Pa$

$P_i=8" "Pa" initial pressure"$

$T_1=210" "^o K" initial temperature"$

$T_2=35" "^o C" ; "T_2=35+273=308 " "^o K$

$P_f=?" final pressure"$

$P_i/T_i=P_f/T_f$

$8/210=P_f/308$

$P_f=(8*308)/210$

$P_f=11.73" "Pa$

The gas inside of a container exerts 8 Pa8 Pa of pressure and is at a temperature of 210 ^o K210 ^o K. If the temperature of the gas changes to 35 ^oC35 ^oC with no change in the container's volume, what is the new pressure of the gas?