The gas inside of a container exerts #8 Pa# of pressure and is at a temperature of #120 ^o K#. If the temperature of the gas changes to #35 ^oC# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2017-04-26T14:46:53

The pressure is #=20.53Pa#

We apply Gay Lussac's Law

#P_1/T_1=P_2/T_2#

The initial pressure is #P_1=8Pa#

The initial temperature is #T_1=120K#

The final temperature is #T_2=273+35=308K#

The final pressure is

#P_2=T_2/T_1*P_1#

#=308/120*8=20.53Pa#