The gas inside of a container exerts 8 Pa of pressure and is at a temperature of 450 ^o K. If the temperature of the gas changes to 90 ^oC with no change in the container's volume, what is the new pressure of the gas?

Dec 12, 2017

The new pressure is $= 6.45 P a$

Explanation:

Apply Gay Lussac's Law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$ at constant volume

The initial pressure is ${P}_{1} = 8 P a$

The initial temperature is ${T}_{1} = 450 K$

The final temperature is ${T}_{2} = 90 + 273 = 363 K$

The final pressure is

${P}_{2} = {T}_{2} / {T}_{1} \cdot {P}_{1} = \frac{363}{450} \cdot 8 = 6.45 P a$