# The gas inside of a container exerts 9 Pa of pressure and is at a temperature of 35 ^o K. If the temperature of the gas changes to 80 ^oK, what is the new pressure of the gas?

Feb 20, 2016

$P \cong 20 , 57 P a$
${P}_{1} / {T}_{1} = \frac{P}{T}$
$\frac{9}{35} = \frac{P}{80}$
$P = \frac{80 \cdot 9}{35}$
$P \cong 20 , 57 P a$