The gas inside of a container exerts $9 Pa$ of pressure and is at a temperature of $250 ^o K$ . If the pressure in the container changes to $5 Pa$ with no change in the container's volume, what is the new temperature of the gas?

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Answer 1 · 2018-05-09T13:36:10

Approximately $138.9$ kelvin.

For constant volume and number of moles, we can use Gay-Lussac's law, which states that,

$PpropT$ or $P_1/P_2=T_1/T_2$ .

So here, we get:

$(9 \ "Pa")/(250 \ "K")=(5 \ "Pa")/T_2$

$T_2=(250 \ "K")/(9color(red)cancelcolor(black)"Pa")*5color(red)cancelcolor(black)"Pa"$

$~~138.9 \ "K"$

The gas inside of a container exerts 9 Pa9 Pa of pressure and is at a temperature of 250 ^o K250 ^o K. If the pressure in the container changes to 5 Pa5 Pa with no change in the container's volume, what is the new temperature of the gas?