The gas inside of a container exerts #9 Pa# of pressure and is at a temperature of #250 ^o K#. If the pressure in the container changes to #5 Pa# with no change in the container's volume, what is the new temperature of the gas?

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Answer 1 · 2018-05-09T13:36:10

Approximately #138.9# kelvin.

For constant volume and number of moles, we can use Gay-Lussac's law, which states that,

#PpropT# or #P_1/P_2=T_1/T_2#.

So here, we get:

#(9 \ "Pa")/(250 \ "K")=(5 \ "Pa")/T_2#

#T_2=(250 \ "K")/(9color(red)cancelcolor(black)"Pa")*5color(red)cancelcolor(black)"Pa"#

#~~138.9 \ "K"#