The graph of #y=ax^2+bx# has an extremum at #(1,-2)#. Find the values of a and b?
2 Answers
May 23, 2018
Explanation:
Given:
From the given can substitute 1 for x and 2 for y and write the following equation:
We can write the second equation using that the first derivative is 0 when
Subtract equation [1] from equation [2]:
Find the value of b by substituting
May 23, 2018
Explanation:
#1# #in# #RR# #f# is differentiable at#x_0=1# #f# has an extremum at#x_0=1#
According to Fermat's Theorem
but
So
and
so