The graph of $y = log_("1/a")x$ is the same as the graph of? 1. $y = -a^x$ 2. $y = log_ax$ 3. $y = (1/a)^x$ 4. $y = -log_ax$ 5. $y = log_a(-x)$

Question

Answer is 4. $y = -log_ax$ .

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Answer 1 · 2018-05-10T06:45:49

$4.y=-log_ax$

As $y=log_(1/a)x$ , we have $(1/a)^y=x$

or $1/a^y=x$

or $a^y=1/x$

or $log_a(1/x)=y$

or $log_a1-log_ax=y$ , but $log_a1=0$

Hence $-log_a x=y$ i.e. answer is 4