The initial population is 250 bacteria, and the population after 9 hours is double the population after 1 hour. How many bacteria will there be after 5 hours?

$p \left(t\right) = 250 \cdot {2}^{\frac{t}{8}}$ where $t$ is measured in hours.
$p \left(5\right) = 250 \cdot {2}^{\frac{5}{8}} \cong 386$