The length of a rectangle is 2 feet more than it's width. How do you find the dimensions of the rectangle if its area is 63 square feet?

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Answer 1 · 2016-12-25T02:14:34

#7# by #9# feet.

We let the length be #x + 2# and the width be #x#.

The area of a rectangle is given by #A = l * w#.

#A = l * w#

#63 = x(x + 2)#

#63 = x^2 + 2x#

#0 = x^2 + 2x - 63#

#0 = (x + 9)(x - 7)#

#x = -9 and 7#

A negative answer is impossible here, so the width is #7# feet and the length is #9# feet.

Hopefully this helps!