# The length of a rectangle is 2 feet more than it's width. How do you find the dimensions of the rectangle if its area is 63 square feet?

Dec 25, 2016

$7$ by $9$ feet.

#### Explanation:

We let the length be $x + 2$ and the width be $x$.

The area of a rectangle is given by $A = l \cdot w$.

$A = l \cdot w$

$63 = x \left(x + 2\right)$

$63 = {x}^{2} + 2 x$

$0 = {x}^{2} + 2 x - 63$

$0 = \left(x + 9\right) \left(x - 7\right)$

$x = - 9 \mathmr{and} 7$

A negative answer is impossible here, so the width is $7$ feet and the length is $9$ feet.

Hopefully this helps!