The length of a rectangle is 5 cm more than twice its width. What is the largest possible width if the perimeter is at most 64 cm?

1 Answer
Aug 13, 2016

width=9cmwidth=9cm

Explanation:

Perimeter of a rectangle=2(a+b)=2(a+b) where aa is the length and bb is the width
As given we can write
a=2b+5a=2b+5 by plugging this value

Perimeter of a rectangle64=2(a+b)64=2(a+b)
or
a+b=64/2a+b=642
or
a+b=32a+b=32
or
2b+5+b=322b+5+b=32
or
3b=32-53b=325
or
3b=273b=27
or
b=27/3b=273
or
b=9b=9