Question

The length of a rectangle is 8 cm greater than the width. The area of the rectangle is 105 cm 2. How do you find the width and the length?

Answer 1

Let `x` be the width of the rectangle and `x+ 8` be the length.

`A = l xx w`

`105= x(x + 8)`

`105 = x^2 + 8x`

`0 = x^2 + 8x - 105`

`0 = (x + 15)(x - 7)`

`x =-15 and 7`

Since a negative length is impossible, the rectangle measures 7 centimetres by `15` centimetres.

Hopefully this helps!