# The overall reaction in the body is described by the equation C6H12O6(aq) + 6O2(g) = 6CO2(g) + 6H2O(l). How many grams of oxygen are required to convert 23.0 g of glucose to CO2 and H2O? What is the number of g of CO2 produced?

Aug 8, 2018

Approx. $25 \cdot g$ with respect to oxygen...

#### Explanation:

You have the stoichiometric equation...

${C}_{6} {H}_{12} {O}_{6} \left(g\right) + 6 {O}_{2} \left(g\right) \rightarrow 6 C {O}_{2} \left(g\right) + 6 {H}_{2} O \left(l\right)$

And the normal rigmarole in these reactions, is to balance the carbons as carbon dioxide, then balance the hydrogens as water, and THEN balance the oxygens.

And thus $180 \cdot g$ of glucose is oxidized by $192 \cdot g$ dioxygen to give $264 \cdot g$ carbon dioxide, and $108 \cdot g$ water...

With respect to glucose we have a molar quantity of...

${n}_{\text{glucose}} = \frac{23.0 \cdot g}{180.16 \cdot g \cdot m o {l}^{-} 1} = 0.128 \cdot m o l$

And thus SIX EQUIV dioxygen are required...

$\text{mass"_"dioxygen} = 0.128 \cdot m o l \times 6 \times 32.00 \cdot g \cdot m o {l}^{-} 1 = 24.5 \cdot g$

And thus SIX EQUIV carbon dioxide are released...

"mass"_"carbon dioxide"=0.128*molxx6xx44.01*g*mol^-1=??*g